Two vibrating strings of the same material but lengths L and 2L have radii 2r and r respectively. They are stretched under the same tension. Both the strings vibrate in their fundamental modes, the one of length L with frequency n1 and the other with frequency n2. The ratio n1n2, is given by
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a
2
b
4
c
8
d
1
answer is D.
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Detailed Solution
Fundamental frequency n = 12lTπr2ρwhere m = Mass per unit length of wire⇒n ∝ = 1lr ⇒n1n2= r2r1×l2l1 = r2r×2LL = 11
Two vibrating strings of the same material but lengths L and 2L have radii 2r and r respectively. They are stretched under the same tension. Both the strings vibrate in their fundamental modes, the one of length L with frequency n1 and the other with frequency n2. The ratio n1n2, is given by