Questions
Two walls of thicknesses d1 and d2 and thermal conductivities K1 and K2 are in contact. In the steady state, if the temperatures at the outer surface are T1 and T2, the temperature at the common wall is:
detailed solution
Correct option is B
Let temperature be T then K1A(T1-T)d1=K2A(T-T2)d2⇒T=K1T1d2+K2T2d1K1d2+K2d1Talk to our academic expert!
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