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Q.

Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is 'a' and the phase of A is ahead by π3 than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter

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a

2a

b

a3

c

a2

d

a

answer is D.

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Detailed Solution

Path difference (∆x) = 50 cm = 12m∴ Phase difference ∆φ = 2πλ×∆x   ⇒ φ = 2π1×12 = πTotal phase difference = π-π3 = 2π3⇒A = a2+a2+2a2cos(2π3) = a
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