First slide

Young's double slit Experiment

Question

Two waves having the intensities in the ratio of 9;1 produce interference. The ratio of maximum to minimum intensity is equal to

Easy

A

10 :8
B

9:1
C

4:1
D

2:1

Solution

Intensity ratio = $= \frac{I_{1}}{I_{2}} = \frac{9}{1}$
Amplitude ratio += $\frac{a_{1}}{a_{2}} = \frac{3}{1}$
If $a_{1} = 3 units, then a_{2} = 1 unit.$
$At maxima a_{max} = a_{1} + a_{2} = 4 At minima a_{min} = a_{1} - a_{2} = 2 \frac{I_{max}}{I_{min}} = \frac{{(a_{max})}^{2}}{{(a_{min})}^{2}} = \frac{16}{4} = \frac{4}{1}$

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