First slide

Introduction-Wave optics

Question

Two waves of intensity I undergo Interference. The maximum intensity obtained is

Easy

A

$\frac{I}{2}$
B

I
C

2I
D

4I

Solution

$For maximum intensity ϕ = 0^{\circ} ∴ I = I_{1} + I_{2} + 2 \sqrt{I_{1} I_{2}} \cos ϕ = I + I + 2 \sqrt{II} \cos 0^{\circ} = 4 I$

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