Two wheels A and C are connected by a belt B as shown in figure. The radius of C is three times the radius of A. What would be the ratio of the rotational inertias IC/IA if both the wheels have the same rotational kinetic energy?
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answer is 9.
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Detailed Solution
As the belt does not slip, vP=vQi.e., rAωA=rCωC [ as v=rω] …(i)According to the given problem if rA=r, rC=3r, so Eq. (i) becomesωA=3ωC …(ii)If both the wheels have the same rotational kinetic energy, then12IAωA2=12ICωC2IAIC=ωCωA2=132=19