First slide
Magnetic field due to a current carrying circular ring
Question

Two wire loops PQRSP formed by joining two semicircular wires of radii -R1, and R2, carries a current as shown in fig. The magnitude of the magnetic 

induction at the centre C is

Moderate
Solution

Magnetic inductions at C due to straight portions PQ and RS will be equal to zero because they are on the same line of centre. Magnetic fields due to semi-circular portions will be just in opposite direction as current through them are opposite.
 B2=μ0i(1/2)2R2 and B1=μ0i(1/2)2R1 B=B1B2=μ0i41R11R2

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