Two wire loops PQRSP formed by joining two semicircular wires of radii -R1, and R2, carries a current as shown in fig. The magnitude of the magnetic induction at the centre C is
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a
μ0i41R1−1R2
b
μ0i21R1−1R2
c
μ0i41R1+1R2
d
μ0i21R1+1R2
answer is A.
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Detailed Solution
Magnetic inductions at C due to straight portions PQ and RS will be equal to zero because they are on the same line of centre. Magnetic fields due to semi-circular portions will be just in opposite direction as current through them are opposite.∴ B2=μ0i(1/2)2R2 and B1=μ0i(1/2)2R1∴ B=B1−B2=μ0i41R1−1R2