Q.
Two wires are made of the same material and have the same volume. The first wire has cross-sectional area A and the second wire has cross-sectional area 3A. If the length of the first wire is increased by ∆l on applying a force F, how much force is needed to stretch the second wire by the same amount?
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a
9F
b
6F
c
4F
d
F
answer is A.
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Detailed Solution
Young's modulus, Y=FlAΔlSince initial volume of wires are same Their areas of cross sections are A and 3 A and lengths are 3l and l respectively.For wire 1,Δl=FAY3l ...........(i) For wire 2 , let F' force is applied F'3A=YΔll⇒Δl=F'3AYl ..........(ii)From the equations (i) and (ii)Δl=FAY3l=F'3AYl⇒F':
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