Questions
Two wires are in unison. If the tension in one of the wires is increased by 2%, 5 beats are produced per second. The initial frequency of each wire is
detailed solution
Correct option is C
n∝T⇒Δnn=ΔT2TIf tension increases by 2%, then frequency must increases by 1%.If initial frequency n1 = n then final frequency n2 – n1 = 5⇒101100n−n=5⇒n=500Hz.Short trick : If you can remember then apply following formula to solve such type of problems.Initial frequency of each wire (n)=(Number of beats heard per sec)×200(per centage change in tension of the wire)Here n=5×2002=500HzSimilar Questions
A metal wire of diameter 1.5 mm is held on two knife edges separated by a distance 50 cm the tension in the wire is 100 N the wire vibrating with its fundamental frequency and vibrating tuning fork together produces 5 beats per second. The tension in the wire is then reduced to 81 N, when the two are excited, beats are heard at the same rate. Calculate frequency of the fork.
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