Two wires are in unison. If the tension in one of the wires is increased by $$2$$%, $$5$$ beats are produced per second. The initial frequency of each wire is

Question

Infinity Learn · Accepted Answer

n∝T⇒Δ$$nn=$$Δ$$T2TIf$$ tension increases by $$2$$%, then frequency must increases by $$1$$%.If initial frequency $$n1$$ $$=$$ n then final frequency $$n2$$ – $$n1$$ $$=$$ $$5$$⇒$$101100n$$−$$n=5$$⇒$$n=500Hz$$.Short trick : If you can remember then apply following formula to solve such type of problems.Initial frequency of each wire (n)=(Number$$ of beats heard per $$sec$$$$)×$$200(per$$ centage change in tension of the $$wire)Here$$  $$n=5$$×$$2002=500Hz$$

Two wires are in unison. If the tension in one of the wires is increased by 2%, 5 beats are produced per second. The initial frequency of each wire is

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