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Two wires A and B are of same materials. Their lengths are in the ratio I : 2 and diameters are in the ratio 2 : I when stretched by force FA and FB respectively they get equal increase in their lengths. Then the ratio FAFB should be

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a

1 : 2

b

1 : 1

c

2 : 1

d

8 : 1

answer is D.

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Detailed Solution

F=Y×A×lL⇒F∝r2L(Y and l are constant )FAFB=rArB2×LBLA=212×21=81

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