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Two wires A and B of same material and same mass have radius 2r and r. If resistance of wire A is 34Ω then resistance of B will be

a
544 Ω
b
372 Ω
c
68 Ω
d
17 Ω

detailed solution

Correct option is A

R=ρ lA and mass m - volume (V) x density (Al) dSince wires have same material so ρ and d is same for both.Also they have same mass ⇒ Al = constant⇒l∝lA⇒ R1R2 = l1l2 ×  A2A1 = A2A12 =  r2r14⇒ 34R2 =r2r4⇒ R2 = 544 Ω

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