First slide

Stress and strain

Question

Two wires of copper having the length in the ratio 4 : 1 and their radii ratio as 1 : 4 are stretched by the same force. The ratio of longitudinal strain in the two will be

Moderate

A

1 : 16
B

16: 1
C

1 : 64
D

64: 1

Solution

$Strain \propto Stress \propto \frac{F}{A}$
Ratio of strain $= \frac{A_{2}}{A_{1}} = {(\frac{r_{2}}{r_{1}})}^{2} = {(\frac{4}{1})}^{2} = \frac{16}{1}$

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