Two wires of different material have same lengths and areas of cross sectoin. What is the ratio of their increase in length when the forces applied are the same ? (Y1=0.60×1011Nm−2 ,Y2=1.80×1011Nm−2 )
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a
3 : 1
b
1 : 3
c
1 : 2
d
2 : 1
answer is A.
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Detailed Solution
y=FLAe (Here F, L, A are same)e∝1y⇒e1e2=y2y1=1.8×10110.6×1011=31