Two wires of equal diameters, of resistivities ρ$$1$$ and ρ$$2$$ and lengths $$l1$$ and $$l2$$, respectively, are joined in series. The equivalent resistivity of the combination is

Correct option is 1ρ1l1 + ρ2l2l1l2

Questions

Two wires of equal diameters, of resistivities $ρ_{1}$ and $ρ_{2}$ and lengths l₁ and l₂, respectively, are joined in series. The equivalent resistivity of the combination is

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ρ1l1 + ρ2l2l1l2

ρ1l2 + ρ2l1l1−l2

ρ1l2 + ρ2l1l1+l2

ρ1l2 − ρ2l1l1−l2

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detailed solution

Correct option is A

R1=ρ1l1 A and R2 ρ2l2A. In series Req =R1+R2ρeq.l1+l2A=ρ1l1 A+ ρ2l2A⇒ ρeq.= ρ1l1 +ρ2l2 l1+l2

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Two wires of equal diameters, of resistivities ρ1 and ρ2 and lengths l1 and l2, respectively, are joined in series. The equivalent resistivity of the combination is

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Ready to Test Your Skills?

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Two wires of equal diameters, of resistivities $ρ_{1}$ and $ρ_{2}$ and lengths l₁ and l₂, respectively, are joined in series. The equivalent resistivity of the combination is