Two wires made of the same material have lengths 2m & 4m and masses 8 gm and 16 gm respectively. When they are subjected to the same force, then the ratio of their elongations is
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a
1 : 2
b
2 : 1
c
1 : 4
d
4 : 1
answer is A.
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Detailed Solution
e=FLAY Here A=VL=mρLe=FL2ρmY∴e∝L2me1e2=(L1L2)2(m2m1)=(24)2(168)=14×2=12