First slide

Elastic behaviour of solids

Question

Two wires of the same diameter and of the same material have the length l and 2l. lf the force F is applied on each, the ratio of the work done in the two wires will be

Moderate

A

1:2
B

1:4
C

2:1
D

1:1

Solution

$\begin{array}{l} W = \frac{1}{2} Fl ∴ W \propto l (F is constant) \\ ∴ \frac{W_{1}}{W_{2}} = \frac{l_{1}}{l_{2}} = \frac{l}{2 l} = \frac{1}{2} \end{array}$

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