Two wires of same diameter of the same material having the length l and 2l. If the force F is applied on each, the ratio of the work done in the two wires will be

Work done,  W=12Fl∴  Work done  W∝l    (If F is constant)  area of cross section and material same so elongation is proportional to original length.⇒ W1W2=ll2=l2l=12