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Two wires of the same material (Young’s modulus = Y) and same length L but radii R and 3R respectively are joined end to end and a weight w is suspended from the combination as shown in the figure. The elastic potential energy in the system is

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answer is 2.

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Detailed Solution

Δl1=wL9πR2Y, Δl2=wLπR2Y∴U=12K1Δl12+12K2Δl22 here K=YAL =12×Y9πR2L×wL9πR2Y2+12×YπR2L×wLπR2Y2 =10w2L18πR2Y

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