Two wires of same metal have same length, but their cross sections are in the ratio 3 : 1. They are joined in series. The resistance of thicker wire is 10Ω.The total resistance of the combination will be
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a
52Ω
b
403Ω
c
40Ω
d
100Ω
answer is C.
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Detailed Solution
We know that R= p(l/A)For same material and same lengthR1R2=A2A1=31 or R1=3R˙2Given, R2=10Ω, hence R1=30ΩIn series, R = R1 +R2=30Ω+10Ω=40Ω
Two wires of same metal have same length, but their cross sections are in the ratio 3 : 1. They are joined in series. The resistance of thicker wire is 10Ω.The total resistance of the combination will be