Two wooden blocks are moving on a smooth horizontal surface such that the mass m remains stationary with respect to the block of mass M as shown in the figure. The magnitude of force P is
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a
(M+m)gtanβ
b
gtanβ
c
mgcosβ
d
(M+m)gcosecβ
answer is A.
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Detailed Solution
Acceleration of the system:a=PM+m ....(i)The FBD of mass m is shown in the figure.Rsinβ=ma ......(i)Rcosβ=mg .....(ii)From Eqs. (ii) and (iii), we geta=gtanβPutting the value of a in (i), we getP=(M+m)gtanβ