In a two-dimensional motion of a particle, the particle moves from point A, with position vector r→1, to point B, with position vector r→2. If the magnitudes of these vectors are, respectively, r1 = 3 and r2 = 4 and the angles they make with the x - axis are find the θ1=75∘ and θ2=15∘, respectively, then of the displacement vector.
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a
15
b
13
c
17
d
15
answer is B.
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Detailed Solution
Displacement =AB→, angle between r→1 and r→2 is θ=75∘−15∘=60∘From figure, AB2=r12+r22−2r1r2cosθ=32+42−2×3×4cos60∘=13⇒ AB=13