A typical nuclear fusion reaction is given by : 1H2+1H2→1H3+1H1+4.0MeV 1H2+1H2→2He4+0n1+17.6MeVThe net result of two reactions is :3×1H2→2He4+0n1+1H1+21.6MeVThe energy released per nucleon of the reactant, in the above thermonuclear reaction is :

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1.8 MeV

3.6 MeV

7.2 MeV

21.6 MeV

answer is B.

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Detailed Solution

31H2→2He4+0n1+1H1+21 . 6MeVenergy released per nucleon=21.66=3.6MeV

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