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$_{92} U^{238}$ decays successively to form $_{90} T h^{234},_{91} P a^{234},_{92} U^{234}$ . The sequence of radiations emitted is

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Correct option is C

92U238→α90Th234→β91Pa234→β92U234when a nucleus emits an alpha particle its mass number decreases by 4 and atomic number decreases by 2.when a nucleus emits a beta particle its atomic number increases by 1.

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92U238 decays successively to form 90Th234,91Pa234,92U234 . The sequence of radiations emitted is

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$_{92} U^{238}$ decays successively to form $_{90} T h^{234},_{91} P a^{234},_{92} U^{234}$ . The sequence of radiations emitted is