U 92238 has 92 protons and 238 nucleons.It decays by emitting an alpha particle and becomes
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a
U 92234
b
U 92235
c
Th 90234
d
Np 93237
answer is C.
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Detailed Solution
Let the daughter nucleus X ZA. So, reaction can be shown asU 92238→X ZA+He 24From conservation of atomic mass238 = A + 4⇒A = 234From conservation of atomic number92 = Z + 2⇒Z=90So, the resultant nucleus is X 90234, i.e., Th 90234.