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Q.

U 92238 has 92 protons and 238 nucleons.It decays by emitting an alpha particle and becomes

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a

U 92234

b

U 92235

c

Th 90234

d

Np 93237

answer is C.

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Detailed Solution

Let the daughter nucleus X ZA. So, reaction can be shown asU 92238→X ZA+He 24From conservation of atomic mass238 = A + 4⇒A = 234From conservation of atomic number92 = Z + 2⇒Z=90So, the resultant nucleus is X 90234, i.e., Th 90234.
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