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A U tube of uniform bore of cross-sectional area A has been set up vertically with open ends facing up. Now m gm of a liquid of density d is poured into it. The column of liquid in this tube will oscillate with a period T such that

a
T=2πMg
b
T=2πMAgd
c
T=2πMgdA
d
T=2πM2Adg

detailed solution

Correct option is D

If the level of liquid is depressed by y cm on one side, then the level of liquid in column P is 2y cm higher than B as shown.The weight of extra liquid on the side P=2Aydg.This becomes the restoring force on mass M.∴ Restoring acceleration  =− 2AydgM This relation satisfies the condition of SHM i.e. a∝−y. Hence time period T=2πDisplacement|Acceleration|   =2πy2AydgM⇒T=2πM2Adg

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