u^1, u^2 and u^3 are three unit vector such that u^1+u^2+u^3=0 . Then the value of u^1.u^2−4 u^3.u^1 is
1.5
2.5
0.5
Zero
Since u^1+u^2+u^3=0 , they must form a closed triangle as shown.
∴ u^1.u^2−4 u^3.u^1=1.1.cos1200−4.1.1cos1200=−12+2=1.5