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Ultraviolet light of wavelength 300 nm and intensity 1.0 W m-2 falls on the surface of a photosensitive material. If one per cent of the incident photons produce photoelectrons, then the number of photoelectrons emitted per second from an area of 1.0 cm2 of the surface is nearly

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a

9.61×1014s−1

b

4.12×1013s−1

c

1.51×1012s−1

d

2.13×1011s−1

answer is C.

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Detailed Solution

n= power hc/λ=300×10−96.6×10−34×3×108 =1.5×1018m−2s−1=1.5×1014s−1As only 1 percent of photons cause emission of photoelectrons, number of photo electrons is ne=1.5×1012s−1

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Ultraviolet light of wavelength 300 nm and intensity 1.0 W m-2 falls on the surface of a photosensitive material. If one per cent of the incident photons produce photoelectrons, then the number of photoelectrons emitted per second from an area of 1.0 cm2 of the surface is nearly