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Q.

Ultraviolet light of wavelength 300 nm and intensity 1.0 watt/m2 falls on the surface of a photosensitive material. If 1% of the  incident photons produce photoelectrons, then the number of photoelectrons emitted from an area of 1.0 cm2 of the surface is nearly

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a

9.61×1014per sec

b

4.12×1013per sec

c

1.51×1012per sec

d

2.13×1011per sec

answer is C.

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Detailed Solution

Intensity of lightI=Wattarea=nhcAλ⇒number  of  photon,  n=IAλhc∴Number  of  photo electron  =1100×IAλhc=11001×104×300×10−96.6×10−34×3×108=1.5×1012per sec.
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