First slide

Photo Electric Effect

Question

Ultraviolet radiation of 6.2 eV falls on an aluminum surface (work function 4.2 eV). The kinetic energy in joule of the fastest electron emitted is approximately

Easy

A

$3 \times 10^{- 21}$
B

$3 \times 10^{- 19}$
C

$3 \times 10^{- 17}$
D

$3 \times 10^{- 12}$

Solution

$h v = W_{0} + K . E 6 \cdot 2 = 4 \cdot 2 + K \cdot E . or K \cdot E . = 2 e V o r K . E . = 2 \times (1 \cdot 6 \times 10^{- 34}) J = 3 \cdot 2 \times 10^{- 19} J$

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