First slide

Finding field strength using Gauss's Law

Question

An uncharged conducing large plate is placed as shown. Now an electric field E towards right is applied. Find the induced charge density on right surface of the plate.

Moderate

A

$- ε_{0} E$
B

$ε_{0} E$
C

$- 2 ε_{0} E$
D

$2 ε_{0} E$

Solution

Net electric field at point P should be zero. For this electric field due to induced charges = applied electric field
$\Rightarrow \frac{σ}{ε_{0}} = E \Rightarrow σ = ε_{0} E$

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