Questions
Under the action of a force, a 2 kg body moves such that its position x as a function of time t is given by x = , where x is in meter and t in seconds. The work done by the force in the first two seconds is:
detailed solution
Correct option is B
v = dxdt = ddt(t33) = t2When t = 0, then v = o, When t = 2, then v = 4 m/sWork done in first two seconds = change in KEW = 12m[(4)2-(0)2] = 122×16 = 16Talk to our academic expert!
Similar Questions
A body of mass 300 kg is moved through 10m along a smooth inclined plane of angle 300. The work done in
moving (in joules) is (Take, g = 9.8 ms-2)
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