First slide

Viscosity

Question

Under a constant pressure head, the rate of flow of orderly volume flow of liquid through a capillary tube is V. If the length of the capillary is doubled and the diameter of the bore is halved, the rate of flow would become

Easy

A

V/4
B

16 V
C

V/8
D

V/32

Solution

we know that $V = \frac{{πPr}^{4}}{8 ηl}$
$In second case, V_{1} = \frac{π (P) (r / 2)^{4}}{8 η (2 l)} = \frac{V}{32}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App