Under a constant pressure head, the rate of flow of orderly volume flow of liquid through a capillary tube is V. If the length of the capillary is doubled and the diameter of the bore is halved, the rate of flow would become

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V/4

16 V

V/8

V/32

answer is D.

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Detailed Solution

we know that V=πPr48ηl In second case, V1=π(P)(r/2)48η(2l)=V32

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