Under the influence of a uniform magnetic field a charged particle is moving in a circle of radius R with constant speed v. The time period of the motion

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depends on v and not on R

depends on both R and v

is independent of both R and v

depends on R and not on v

answer is C.

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Detailed Solution

To move on circular path in a magnetic field, a centripetal force is provided by the magnetic force. When magnetic field is perpendicular to motion of charged particle, thenCentripetal force = magnetic forceThat is mv2R =Bqv or R=mvBqFurther, time period of the motionT=2πRv =2πmvBqv or T=2πmBqIt is independent of both R and v.

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