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Q.

Under the influence of a uniform magnetic field a charged particle is moving in a circle of radius R with constant speed v. The time period of the motion

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a

depends on v and not on R

b

depends on both R and v

c

is independent of both R and v

d

depends on R and not on v

answer is C.

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Detailed Solution

To move on circular path in a magnetic field, a centripetal force is provided by the magnetic force. When magnetic field is perpendicular to motion of charged particle, thenCentripetal force = magnetic forceThat is mv2R =Bqv  or R=mvBqFurther, time period of the motionT=2πRv =2πmvBqv  or  T=2πmBqIt is independent of both R and v.
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