First slide

Travelling wave

Question

An underwater sonar source operating at a frequency of 60 KHz directs its beam towards the surface. If the velocity of sound in air is 330 m/s, the wavelength and frequency of waves in air are:

Easy

A

5.5 mm, 60 KHz
B

330 m, 60 KHz
C

5.5 mm, 20 KHz
D

5.5 mm, 80 KHz

Solution

Frequency of waves remains same, i.e. 60 Hz
and wavelength $ λ = \frac{v}{n} = \frac{330}{60 \times 10^{3}}$ = 5.5 mm.

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