A uniform chain of length I and mass M is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on to the table is

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Infinity Learn · Accepted Answer

The situation is shown in fig. (9).Given that the length of hanging part is $$L/3$$,  so its mass would be $$M/3$$.Hence the weight (Mg/3) will act at the center of gravity G of hanging part. It will act at a distance (L/6) $$)$$ below the surface of table. Work done in pulling the hanging part on the table $$=$$ increase in P.E.$$=m$$×g×$$h=M3$$×g×$$L6=mgL18$$

A uniform chain of length I and mass M is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on to the table is

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