First slide

Work

Question

A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on to the table is

Moderate

A

MgL
B

MgL/3
C

MgL/9
D

MgL/18

Solution

$W = \frac{MgL}{2 n^{2}} = \frac{MgL}{2 {(3)}^{2}} = \frac{MgL}{18}$ (n = 3 given)

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