First slide

Work done by Diff type of forces

Question

A uniform chain of length 2 m is kept on a table such that a length of60 cm hangs freely from the edge of the table. The total mass of the chain is 4 kg. What is the work done in pulling the entire chain on the table ?

Moderate

A

7.2 J
B

3.6 J
C

120J
D

1200J

Solution

see fig
$Mass per unit length = \frac{M}{L} = \frac{4}{2} = 2 kg / m Mass of the hanging chain = 0 \cdot 6 \times 2 = 1 .2 kg Centre of mass of the hanging part = \frac{0 \cdot 6 + 0}{2} = 0 \cdot 3 m Work done in pulling the chain on the table is equal to work done agaitrst gravity W = mgh = 1 \cdot 2 \times 10 \times 0 \cdot 3 = 3 \cdot 6 j o u l e$

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