A uniform circular disc of radius a is taken. A circular portion of radius b has been removed from it as shown in the figure. If the centre of hole is at a distance c from the centre of the disc, the distance $$x2$$ of the centre of mass of the remaining part from the initial centre of mass O is given by

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Infinity Learn · Accepted Answer

Centre of mass of remaining portion was at point $$O2$$. Hence, $$x2$$ (area$$ of remaining $$portion) $$=$$ c (area$$ of $$removeddisc)∴          $$x2$$$$π$$$$a2-$$π$$b2=c$$$$π$$$$b2$$⇒$$x2=cb2a2-b2$$

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