A uniform circular disc of radius a is taken. A circular portion of radius b has been removed from it as shown in the figure. If the centre of hole is at a distance c from the centre of the disc, the distance x2 of the centre of mass of the remaining part from the initial centre of mass O is given by
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a
πb2(a2-c2)
b
cb2(a2-b2)
c
πc2(a2-b2)
d
ca2(c2-b2)
answer is B.
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Detailed Solution
Centre of mass of remaining portion was at point O2. Hence, x2 (area of remaining portion) = c (area of removeddisc)∴ x2πa2-πb2=cπb2⇒x2=cb2a2-b2
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A uniform circular disc of radius a is taken. A circular portion of radius b has been removed from it as shown in the figure. If the centre of hole is at a distance c from the centre of the disc, the distance x2 of the centre of mass of the remaining part from the initial centre of mass O is given by