A uniform circular disc of radius a is taken. A circular portion of radius b has been removed from it as shown in the figure. If the centre of hole is at a distance c from the centre of the disc, the distance x2 of the centre of mass of the remaining part from the initial centre of mass O is given by
Centre of mass of remaining portion was at point O2. Hence, x2 (area of remaining portion) = c (area of removed
disc)