A uniform cube of mass M and side a is placed on a frictionless horizontal surface. A vertical force F is applied to the edge as shown in figure. Match the Column I with Column II and mark the correct choice from the given codes.Codes

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i -p, ii -q, iii-s, iv-r

i -r. ii - s, iii -q, iv-p

i - q, ii - r, iii - p, iv - s

i - s. ii -p, iii -r, iv-q

answer is C.

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Detailed Solution

From figure, Moment of force F about A,τ1 = F ×a, anticlockwise.Moment of weight Mg of cube about A,τ2 = Mg ×a2 , clockwiseThe cube will not exhibit any motion, if τ1 = τ2or F x a = Mg×a2 or F > Mg2 The cube will rotate only, when τ1 > τ2F ×a > Mga2 or F > Mg2If we assume that normal reaction is effective at a3 from A, then block would turn ifMg × a3 = F ×a or F = Mg3When F = Mg4 < Mg3, there will be no motion.Hence, we conclude (i) - q: (ii) - r; (iii) -p; (iv) - s.

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