Questions

A uniform current carrying ring of mass m and radius R is connected by a mass less string as shown in figure. A uniform magnetic field B₀, exists in the region to keep the ring in horizontal position, then the current in the ring is (l = length of string)

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mgπRB0

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detailed solution

Correct option is A

Torque due to magnetic field τmag =MB0=iπR2B0 Torque due to weight about the point where string is connected τweight =mgR................(ii) If ring remains horizontal, then τmag =τweight iπR2B0=mgR⇒i=mgπRB0

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