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Q.

A uniform current carrying ring of mass m and radius R is connected by a massless string as shown in Fig. A uniform magnetic field B0 exists in the region to keep the ring in horizontal position, then the current in the ring is (l = length of string)

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a

mgπRB0

b

mgRB0

c

mg3πRB0

d

mglπR2B0

answer is A.

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Detailed Solution

Torque due to magnetic field = iB0.πR2Torque due to the mass = mg.RNow mg.R=iB0.πR2⇒i=mgπB0R
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