Questions
A uniform current carrying ring of mass m and radius R is connected by a massless string as shown in Fig. A uniform magnetic field exists in the region to keep the ring in horizontal position, then the current in the ring is (l = length of string)
detailed solution
Correct option is A
Torque due to magnetic field = iB0.πR2Torque due to the mass = mg.RNow mg.R=iB0.πR2⇒i=mgπB0RTalk to our academic expert!
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A charged beam consisting of electrons and positrons enter into a region of uniform magnetic field B perpendicular to field, with a speed v. The maximum separation between an electron and a positron will be (mass of electron = mass of positron = m)
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