A uniform cylinder has a radius R and length L. If the moment of inertia of this cylinder about an axis passing through its centre and normal to its circular face is equal to the moment of inertia of the same cylinder about an axis passing through its centre and normal to its length;then:
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a
L = R
b
L = 3R
c
L = R3
d
L = 0
answer is B.
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Detailed Solution
Given I1 = I2⇒12mR2 = mL212+mR24solve to get L = 3R