A uniform cylinder of mass M and radius R is to be pulled over a step of height a (a
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a
Mg1−a2R2
b
Mg1−R−aR2
c
MgRR−a2−1
d
MgaR
answer is B.
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Detailed Solution
Assume no slipping about PTorque of F about P> torque of gravity⇒FR>Mgx⇒FR>MgRsinθ⇒Fmin=Mgsinθ=MgxR=MgR2−R−a2Rfrom figure opp=Hyp2−adj2=MgR2−R−a2R2=Mg1−R−aR2