A uniform disc of mass 5kg and radius 1m is placed vertically on a rough horizontal surface. A horizontal time varying force is applied on the centre of disc and its variation with time is shown in the graph. The co-efficient of friction between disc and surface is 0.4(Take g=10m/s2)Then which of the following option is/are correct
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a
at t = 3 sec disc is rolling without slipping
b
at t = 4sec disc is rolling without slipping
c
at t = 7sec disc is rolling without slipping
d
at t = 3sec friction force is 10N
answer is A.
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Detailed Solution
From graph , F as function of time is F=10tTranslation : F-f = ma Rotation : f R=mR22aR ⇒f=ma2 ⇒f=F3=10t3 For pure rolling f≤μmg ⇒10t3≤20 ⇒t≤6s Means , slipping will start after 6 sec. Since, f=10t3 Put t=3 sec, ⇒f=10 N
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A uniform disc of mass 5kg and radius 1m is placed vertically on a rough horizontal surface. A horizontal time varying force is applied on the centre of disc and its variation with time is shown in the graph. The co-efficient of friction between disc and surface is 0.4(Take g=10m/s2)Then which of the following option is/are correct