A uniform disc of mass m is fitted (pivoted smoothly) with a rod of mass $\frac{m}{2}$ . If the bottom of the rod is pulled with a velocity v, it moves without changing its angle of orientation and the disc rolls without sliding. Thd kinetic energy of the system (rod + disc) is.

Question

Infinity Learn · Accepted Answer

Rolling can be considered as pure rotation about point of contactKrolling $$=$$ $$12IP$$ω$$2$$ $$=$$ $$12(mR22+mR2)$$ω$$2$$ $$=$$ $$34mR2$$ω$$2-----------(i)The$$ rod translates with the velocity v hence velocity of centre of disc will also be vv $$=$$ ω$$R------(ii)From$$ (i) and (ii); Krolling $$=$$ $$34mv2Kinetic$$ energy of the rod Krod $$=$$ $$12(m2)v2$$ $$=$$ $$mv24-------(iii)Ktotal$$ $$=$$ $$Krolling+Krod$$ $$=$$ $$mv2$$

A uniform disc of mass m is fitted (pivoted smoothly) with a rod of mass $\frac{m}{2}$ . If the bottom of the rod is pulled with a velocity v, it moves without changing its angle of orientation and the disc rolls without sliding. Thd kinetic energy of the system (rod + disc) is.

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A uniform disc of mass m is fitted (pivoted smoothly) with a rod of mass m2. If the bottom of the rod is pulled with a velocity v, it moves without changing its angle of orientation and the disc rolls without sliding. Thd kinetic energy of the system (rod + disc) is.

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A uniform disc of mass m is fitted (pivoted smoothly) with a rod of mass $\frac{m}{2}$ . If the bottom of the rod is pulled with a velocity v, it moves without changing its angle of orientation and the disc rolls without sliding. Thd kinetic energy of the system (rod + disc) is.