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Questions  

A uniform disc of mass M and radius R is mounted on an axle supported in frictionless bearings. A light cord is wrapped around the rim of the disc and a steady downward pull T is exerted on the cord. If we hang a body of mass m from the cord, the tangential acceleration of a point on rim of  the disc is

a
mgM+m
b
mgM+2m
c
2mgM+2m
d
M+2m2mg

detailed solution

Correct option is C

Tangential aceleration a = rα = R (2TMR) = 2TMT = Ma2Now mg-T = ma or mg-Ma2 = maor mg = (m+M2)a or a = 2mgM+2m

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