A uniform disc of mass M and radius R is mounted on an axle supported in frictionless bearings. A light cord is wrapped around the rim of the disc and a steady downward pull T is exerted on the cord by attaching a mass m at the free end of cord. The tension in the cord is
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a
mgM+m
b
MmgM+2m
c
M+2mMmg
d
none of these
answer is B.
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Detailed Solution
Torque is given by the equation τ =TR=Iαhere T=m(g-a)then m(g-a)R = MR22 aRtherefore T=m(g-a) = MmgM+2m