A uniform disc of mass M and radius R is mounted on an axle supported in frictionless bearings. A light cord is wrapped around the rim of the disc and a steady downwardpull T is exerted on the cord. The angular acceleration of the disc is
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a
TMR
b
MRT
c
2TMR
d
MR2T
answer is C.
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Detailed Solution
Torque exerted on the discτ=TR Now τ=Iα α=τI=TR12MR2=2TRMR2=2TMR