First slide

Torque

Question

A uniform disc of radius 20 cm and mass 2kg is fixed at its centre and can rotate about an axis through the centre and perpendicular to its plane. A massless cord is round along the rim of the disc. If a uniform force 2 newton is applied on the cord, tangential acceleration of a point on the rim of the disc will be:

Moderate

A

1 m/s²
B

2 m/s²
C

3.2 m/s²
D

1.6 m/s²

Solution

$From τ = Iα, where I = \frac{MR}{2}$
$(2) (0 .2) = [\frac{2 (0 .2)^{2}}{2}] α \Rightarrow α = 10 rad / s^{2}$
Linear acceleration = $= αR = (10) (0 .2) = 2 m / s^{2}$

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