Q.

A uniform electric field having a magnitude E0 and direction along the positive X-axis exists. If the potential Vis zero at x = 0, then its value at X = +x will be

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a

Vx=+xE0

b

Vx=-xE0

c

Vx=+x2E0

d

Vx=-x2E0

answer is B.

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Detailed Solution

∵E=-dVdX⇒Vx=-xE0
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