A uniform electric field of magnitude 325 V/m is directed in the negative y direction in figure. The coordinates of point A are (-0.2 m, -0.3 m) and those of point B are (0.4 m, 0.5 m). Calculate the potential difference VB−VA (in volts), along the path shown in the figure.

The potential difference between two points A and B in electric field as, VB−VA=−∫AB E→⋅d→rHere the electric field is constant, here we can write the potential difference between points A and B asVB−VA=−ExxB−xA+EyyB−yA=−[(−325){(0.5)−(−0.3)} +0]    (Ey=0)=325×0.8=260 V⇒VB−VA=+260 V